The displacement $(x)$ - time $(t)$ graph of a particle in one dimension motion is as shown in the figure, the average speed is greatest in the interval:

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Solution

The correct option is B $4$
$\to v = \frac{d \to x}{d t}$
Slope of $x - t$ graph is the greatest in the interval 4
or average speed is magnitude of velovity, which is rate of change of distance with time, which is maximum in 4

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The displacement (x)- time (t) graph of a particle in one dimension motion is as shown in the figure, the average speed is greatest in the interval:

The correct option is B 4→v=d→xdtSlope of x−t graph is the greatest in the interval 4or average speed is magnitude of velovity, which is rate of change of distance with time, which is maximum in 4

The displacement $(x)$ - time $(t)$ graph of a particle in one dimension motion is as shown in the figure, the average speed is greatest in the interval:

The correct option is B $4$
$\to v = \frac{d \to x}{d t}$
Slope of $x - t$ graph is the greatest in the interval 4
or average speed is magnitude of velovity, which is rate of change of distance with time, which is maximum in 4