Question

The displacement $y$ in centimeters is given in terms of time $t$ in second by the equation: $y=3\sin 3.14t+4\cos 3.14t$, then the amplitude of SHM is

• A. 3 cm
• B. 4 cm
• C. 5 cm
• D. 7 cm

Answer 1

The correct option is C 5 cm

When the displacement of a SHM is $y=a\sin wt+b\cos wt$, the amplitude of the SHM will be $A=\sqrt{a^2+b^2}$

Here, $a=3,b=4$ so amplitude $A=\sqrt{3^2+4^2}=5$ cm