The displacement y of a particle executing periodic motion is given by y=4cos2(t/2)sin(100t) This expression may be considered to be a result of the super position of
A
2
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B
3
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C
4
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D
5
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Solution
The correct option is B 3 By using simple trigonometric formulas, we can easily see that it is the result of super position of 3 SHM's. y=4cos2(t/2)sin(100t)⇒y=2(1+cost)sin(100t)⇒y=2sin(100t)+2cos(t)sin(100t)⇒y=2sin(100t)+sin(101t)−sin(99t)