The displacement y of a wave travelling in the x-direction is given by y-10-4sin600t-2x-2 metres- Where x is expressed in metre and t in second- The speed of the wave motion is

The displacement due to a wave moving in the positive x - direction is given by y = $\frac{1}{(1 + x^{2})}$ at time t = 0 and by y = $\frac{1}{1 + {(x - 1)}^{2}}$ at t = 2 second, where x and y are in metre. The velocity of the wave in m/s is

Q. A wave is represented by the equation

y = A s i n (10 π x + 15 π t + \frac{π}{3})

where x is in metre and t is in second. The expression represents

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The displacement y of a wave travelling in the x-direction is given by y=10−4sin(600t−2x+π2) metres. Where x is expressed in metre and t in second. The speed of the wave motion is

The correct option is A 300 m/sy=10−4sin(600t−2xt+π2)y=Asin(ωt−kx)ω=600k=2V=ωk=300in/sec

The displacement y of a wave travelling in the x-direction is given by $y = 10^{- 4} sin (600 t - 2 x + \frac{π}{2})$ metres. Where x is expressed in metre and t in second. The speed of the wave motion is

The correct option is A 300 m/s
$y = 10^{- 4} s i n (600 t - 2 x t + \frac{π}{2})$
$y = A s i n (ω t - k x)$
$ω = 600$
k=2
$V = \frac{ω}{k}$
$= 300 i n / s e c$