The $I P_{1^{'}} I P_{2^{'}} I P_{3^{'}} I P_{4^{'}}$ and $I P_{5}$ of an element are $7.1, 14.3, 34.5, 46.8, 162.2$ eV respectively. The element is likely to be:

N a

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S i

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F

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C a

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Solution

The correct option is C $S i$
From given data, it can be seen that,
The difference of $I P_{4} a n d I P_{5}$ is maximum.
So its valency = 4.
Generally, group 14th has valency 4.
So group = IV $A$ or 14th.
Thus, element belongs to Carbon family.
Among given options, Si belongs to carbon family so it must be Si.

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Q. The

{I P}_{1}, {I P}_{2}, {I P}_{3}, {I P}_{4}

and

{I P}_{5}

of an element are

7.1, 14.3, 34.5, 46.8, 162.2 e V

respectively.

The element is likely to be:

The IP1, IP2, IP3, IP4 and IP5 of an element are 7.1, 14.3, 34.5, 46.8, 162.2 eV respectively. The element is likely to be -

The $I P_{1}, I P_{2}, I P_{3}, I P_{4}, I P_{5}$ of an element are 7.1, 14.3, 34.5, 46.8, 162.2 eV respectively. Which element among the following would that be?

Q. The values of

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and

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The IP1′ IP2′ IP3′ IP4′ and IP5 of an element are 7.1,14.3,34.5,46.8,162.2 eV respectively. The element is likely to be:

The correct option is C SiFrom given data, it can be seen that,The difference of IP4andIP5 is maximum. So its valency = 4. Generally, group 14th has valency 4.So group = IVA or 14th. Thus, element belongs to Carbon family.Among given options, Si belongs to carbon family so it must be Si.

The $I P_{1^{'}} I P_{2^{'}} I P_{3^{'}} I P_{4^{'}}$ and $I P_{5}$ of an element are $7.1, 14.3, 34.5, 46.8, 162.2$ eV respectively. The element is likely to be: