The $p H$ of milk, black coffee, tomato juice, lemon juice and egg white are $6.8, 5.0, 4.2, 2.2$ and $7.8$ respectively. Calculate corresponding hydrogen ion concentration in each.

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Solution

$P H = - l o g [H^{+}]$
Hence, $[H^{+}] = 10^{- p H}$
Milk: $[H^{+}] = 10^{- 6.8} = 1.58 \times 10^{- 7} M$
Black coffee: $[H^{+}] = 10^{- 5.0} = 1 \times 10^{- 5} M$
Tomato juice: $[H^{+}] = 10^{- 4.2} = 6.31 \times 10^{- 5} M$
Lemon juice: $[H^{+}] = 10^{- 2.2} = 6.31 \times 10^{- 3} M$
Egg white: $[H^{+}] = 10^{- 7.8} = 1.58 \times 10^{- 8} M$

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The pH of milk, black coffee, tomato juice, lemon juice and egg white are 6.8,5.0,4.2,2.2 and 7.8 respectively. Calculate corresponding hydrogen ion concentration in each.

PH=−log[H+]Hence, [H+]=10−pHMilk: [H+]=10−6.8=1.58×10−7MBlack coffee: [H+]=10−5.0=1×10−5MTomato juice: [H+]=10−4.2=6.31×10−5MLemon juice: [H+]=10−2.2=6.31×10−3MEgg white: [H+]=10−7.8=1.58×10−8M

The $p H$ of milk, black coffee, tomato juice, lemon juice and egg white are $6.8, 5.0, 4.2, 2.2$ and $7.8$ respectively. Calculate corresponding hydrogen ion concentration in each.