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Question

The dissociation constant for the weak acid HA is 105. What will be the pH of an equimolar solution of HA and NaA?

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Solution

Ka=105

pKa=logKa=5

Equiolar concentration of [HA] and [NaA] means concentrations are equal.

Formula from hinderson's equation:

pH=pKa+log[Salt][Acid]

let the concentration of Salt and acid be x molar each.

pH=5+log[Salt][Acid]=5+logxx=5+0=5

pH=5

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