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Question

The dissociation constant (Ka) and percent of degree of dissociation (α) of a weak monobasic acid solution of 0.1 M with a pH=5 are respectively :

A
109, 1
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B
109, 104
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C
109, 102
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D
105, 102
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Solution

The correct option is C 109, 102

HXH++X

let the amount dissociated be x

so concentration of monobasic acid now is 0.1x

concentration of H+ formed=x

Concentration of X formed =x

Ka=[H+][X][HX]

given x=105

so Ka=X20.1

Ka=109

Dissociation percentage =1050.1×100=102


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