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Question

The dissociation constant of monobasic acid is1.6×10-5 and the molar conductivity at infinite dilution is 380×10-4Sm2mol-1. The specific conductance of the 0.01M acid solution is


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Solution

Step 1: Given data

Dissociation constant=1.6×10-5

Molar conductivity at infinite dilution=380×10-4Sm2mol-1

Concentration of acid=0.01M

Step 2: Calculating specific conductance

degree of dissociation(α)=dissociationconstantconcentrationofacid

α=1.6×10-50.01M0.04

Also, α=molarconductivitymolarconductivityatinfinitedilution

0.04=λm380×10-4

λm=0.00152Sm2mol-1or15.2Scm2mol-1

Also, λm=1000kc

15.2=1000k0.01

k=1.52×10-4Scm-1or1.52×10-2Sm-1

Therefore, the specific conductance of the 0.01M acid solution is 1.52×10-2Sm-1


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