The dissociation energy of $H_{2}$ is $430.53 K J m o l e^{- 1}$ . If $H_{2}$ is dissociated by radiation of wavelength $253.7 m m$ . The fraction of radiant energy which will be converted into kinetic energy is

84%

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8.74%

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3.33%

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100%

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Solution

The correct option is B
8.74%

Total energy

$E = \frac{6.625 \times 10^{34} \times 3 \times 10^{8}}{253.7 \times 10^{- 9}} \times \frac{6 \times 10^{23}}{10^{3}} k j$

$0.47185 \times 10^{3}$

= $471.85 k j$

Disslciation energy = $430.53$

Remaining enery = $471.85 - 430.53$

= $41.32 k j$

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The dissociation energy of $H_{2} i s 430.53 k J m o l^{- 1} . I f H_{2}$ is dissociated by illumination with radiation of wavelength $253.7 n m$ , the fraction of the radiant energy which will be converted into kinetic energy is given by

The dissociation energy of $H_{2}$ is 430.53 kJ $m o l^{- 1}$ . If hydrogen is dissociated by illumination with radiation of wavelength 253.7 nm, the fraction of the radiant energy which will be converted into kinetic energy is given by

Q. The dissociation energy of

H_{2}

is 430.53 kJ/mol. If

H_{2}

is exposed to a radiation of wavelength of 253.7 nm, what percent of radiant energy will be converted into kinetic energy?

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The dissociation energy of H2 is 430.53 KJ mole−1. If H2 is dissociated by radiation of wavelength 253.7 mm. The fraction of radiant energy which will be converted into kinetic energy is

The correct option is B 8.74% Total energy E = 6.625 × 1034 × 3 × 108253.7 × 10−9 × 6 × 1023103kj 0.47185 × 103 = 471.85kj Disslciation energy = 430.53 Remaining enery = 471.85 − 430.53 = 41.32kj

The dissociation energy of $H_{2}$ is $430.53 K J m o l e^{- 1}$ . If $H_{2}$ is dissociated by radiation of wavelength $253.7 m m$ . The fraction of radiant energy which will be converted into kinetic energy is

The correct option is B
8.74%

Total energy

$E = \frac{6.625 \times 10^{34} \times 3 \times 10^{8}}{253.7 \times 10^{- 9}} \times \frac{6 \times 10^{23}}{10^{3}} k j$

$0.47185 \times 10^{3}$

= $471.85 k j$

Disslciation energy = $430.53$

Remaining enery = $471.85 - 430.53$

= $41.32 k j$