The dissociation of $C O_{2}$ can be expressed as $2 C O_{2} ⇌ 2 C O + O_{2}$ . If the $2 m o l$ of $C O_{2}$ is take initially and $40 %$ of the $C O_{2}$ is dissociatated completely. What is the total number of moles at equilibrium.

2.4

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2.0

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Solution

The correct option is A $2.4$
$2 C O_{2} \to 2 C O + O_{2}$
At t= 0, 2 moles 0 0

At equilibrium
$2 - 0.4 \times 2$ $0.8$ $0.4$
$1.2$

Total moles = 1.2 +0.8 + 0.4 = 2.4 moles

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The dissociation of CO2 can be expressed as 2CO2⇌2CO+O2. If the 2 mol of CO2 is take initially and 40% of the CO2 is dissociatated completely. What is the total number of moles at equilibrium.

The correct option is A 2.4 2CO2 → 2CO+ O2At t= 0, 2 moles 0 0At equilibrium 2−0.4×2 0.8 0.4 1.2Total moles = 1.2 +0.8 + 0.4 = 2.4 moles

The dissociation of $C O_{2}$ can be expressed as $2 C O_{2} ⇌ 2 C O + O_{2}$ . If the $2 m o l$ of $C O_{2}$ is take initially and $40 %$ of the $C O_{2}$ is dissociatated completely. What is the total number of moles at equilibrium.

The correct option is A $2.4$
$2 C O_{2} \to 2 C O + O_{2}$
At t= 0, 2 moles 0 0

At equilibrium
$2 - 0.4 \times 2$ $0.8$ $0.4$
$1.2$

Total moles = 1.2 +0.8 + 0.4 = 2.4 moles