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Byju's Answer
Standard XII
Chemistry
Abnormal Colligative Properties
The dissoluti...
Question
The dissolution of
A
l
(
O
H
)
3
by a solution of
N
a
O
H
results in the formation of:
A
[
A
l
(
H
2
O
)
4
(
O
H
)
2
]
+
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B
[
A
l
(
H
2
O
)
3
(
O
H
)
3
]
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C
[
A
l
(
H
2
O
)
2
(
O
H
)
4
]
–
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D
[
A
l
(
H
2
O
)
6
]
(
O
H
)
3
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Solution
The correct option is
C
[
A
l
(
H
2
O
)
2
(
O
H
)
4
]
–
A
l
(
O
H
)
3
dissolves in
N
a
O
H
solution to give
[
A
l
(
O
H
)
4
]
−
ion which forms an octahedral complex species
[
A
l
(
O
H
)
4
(
H
2
O
)
2
]
−
A
l
(
O
H
)
3
N
a
O
H
(
a
q
)
2
H
2
O
−
−−
→
[
A
l
(
O
H
)
4
(
H
2
O
)
2
]
−
a
q
+
N
a
+
(
a
q
)
Suggest Corrections
0
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The dissolution of
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by a solution of NaOH results in the formation of:
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Complete hydrolysis of XeF
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Since
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.
)
If the solution also contains a strongly basic anion such as
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−
3
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r
S
2
−
further ionization of hydrated aluminium ions can occur
[
A
l
(
H
2
O
)
4
(
O
H
)
2
]
+
(
a
q
.
)
+
C
O
2
−
3
(
a
q
.
)
⇌
[
A
l
(
H
2
O
)
3
(
O
H
)
3
]
(
s
o
l
i
d
)
+
H
C
O
−
3
(
a
q
.
)
Behaviour of the cation in
C
O
2
−
3
solution in the above passage can be considered as:
Q.
F
e
(
O
H
)
3
and
A
l
(
O
H
)
3
ppt. can be separated by
N
a
O
H
when
A
l
(
O
H
)
3
becomes soluble due to the formation of
N
a
A
l
O
2
and
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e
(
O
H
)
3
remains insoluble.
Q.
F
e
(
O
H
)
3
can be separated from
A
l
(
O
H
)
3
by addition of:
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