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Question

The distance between (0,1,1) and the point of intersection of the line x2=y13=z+14 and the plane x+y+z=9 is

A
29
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B
1229
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C
49
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D
2929
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Solution

The correct option is A 29
x2=y13=z+14x=2t,y=1+3t,z=1+4tx+y+z=92t+1+3t1+4t=99t=9t=1(x,y,z)=(2,4,3)distance=4+9+16=29Hence,optionAiscorrectanswer.

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