The distance between $2 + 8 i$ and $3 + 6 i$ is

\sqrt{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 \sqrt{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{5}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $\sqrt{5}$
Given

The Given numbers are $2 + 8 i$ and $3 - 6 i$

The distance between numbers is given as
$= \sqrt{(2 - 3)^{2} + (8 - 6)^{2}}$
$= \sqrt{1 + 4}$
$= \sqrt{5}$

Suggest Corrections

Similar questions

2 + 8 i

3 - 6 i

Δ = ∣ ∣ ∣ ∣ ∣ \begin{matrix} \sqrt{6} & 2 i & 3 + \sqrt{6} \sqrt{12} & \sqrt{3} + \sqrt{8 i} & 3 \sqrt{2} + \sqrt{6 i} \sqrt{18} & \sqrt{2} + \sqrt{12} i & \sqrt{27} + 2 i \end{matrix} ∣ ∣ ∣ ∣ ∣

Δ

x

y

\frac{x}{1 + 2 i} + \frac{y}{3 + 2 i} = \frac{5 + 6 i}{- 1 + 8 i}

Join BYJU'S Learning Program