The distance between 2nd crest and 6th trough of a wave shown below is 24 cm. If the wave velocity of the moving crest is 20 m s−1, then frequency of rocking of the boat is:
A
24 Hz
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B
20 Hz
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C
375 Hz
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D
240 Hz
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Solution
The correct option is C 375 Hz Distance between 2nd crest and 6th through =4λ+λ2=9λ2 9λ2=24cm λ=24×29cm=489cm V=20ms−1 v=Vλ=2048×9×100Hz =375Hz