Question

The distance between $3^{rd}$ & $2^{nd}$ Bohr orbit $H{e}^{+}$ is

• A. $2.645A^o$
• B. $1.322A^o$
• C. $0.2645A^o$
• D. $Noneofthese$

Answer 1

Answer: (A)

$2.645A^o$

Dis\tance between the $2^{nd}$ and the $3^{rd}$ orbits=distance of $3^{rd}$ orbit-distance of second orbit from the nucleus

$d_3=0.529\times \frac{n^2}{z}\times {10}^{-10}m=0.529\times 9\times {10}^{-10}m$

$d_2=0.529\times 4\times {10}^{-10}m{d}_3-d_2=0.529\times 5\times {10}^{-10}m=2.645\times {10}^{-10}m=2.645A^0$

Hence,

option $\left(A\right)$ is correct answer.