Question

The distance between 3rd and 2nd orbits in the hydrogen atom is:

• A. $2.646\times {10}^{-8}cm$
• B. $2.116\times {10}^{-8}cm$
• C. $1.058\times {10}^{-8}cm$
• D. $2.646\times {10}^{-10}cm$

Answer 1

The correct option is A $2.646\times {10}^{-8}cm$

Solution:

Distance between the 2^nd and the 3^rd orbits = distance of 3^rd orbit – distance of second orbit from the nucleus.

$d_3=\frac{0.529\times n^2}{z\times {10}^{-10}m}$

$=0.529\times 9\times {10}^{-10}m$

$d_2=0.529\times 4\times {10}^{-10}m$

$d_3–d_2=0.529\times 5\times {10}^{-10}m$

$=2.645\times {10}^{-10}m$ is the distance between the 2^nd the 3^rd orbits.