The distance between $(6, 5)$ and $(- 3, 4)$ is

\sqrt{82}

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\sqrt{83}

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\sqrt{84}

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None.

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Solution

The correct option is A $\sqrt{82}$
The given points are $(6, 5)$ and $(- 3, 4)$

The distance is given as
$= \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(6 + 3)^{2} + (4 - 5)^{2}} = \sqrt{9^{2} + 1^{2}} = \sqrt{81 + 1} = \sqrt{82}$

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81 \times 82 \times 83 \times 84 \dots . . 89

A = 4 + \frac{5}{8} + \frac{6}{8^{2}} + \frac{3}{8^{3}} + \frac{7}{8^{4}} a n d B = 4 + \frac{5}{8} + \frac{5}{8^{2}} + \frac{7}{8^{3}} + \frac{6}{8^{4}} .

81 \times 82 \times 83 \times 84 \times 85 \times 86 \times 87 \times 88 \times 89

82^{361} + 83^{361} + 84^{361} + 85^{361} + 86^{361}

81 \times 82 \times 83 \times 84 \times 85 \times 86 \times 87 \times 88 \times 89

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