The distance between a maximum and the adjacent minimum displacement is 5 cm. If the speed of the sound wave is 330 m/s, then the frequency of the sound wave is equal to
A
3300 Hz
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B
6600 Hz
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C
1650 Hz
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D
825 Hz
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Solution
The correct option is C 1650 Hz
Let the wavelength of the wave be λ.
From the figure: OC=λ⇒AB=λ4⇒λ=4×AB=20cm=0.2m(∵AB=5cm)
Speed of sound wave, v=330m/s
Let the frequency of sound wave be f.
Now,f=vλ⇒f=3300.2(∵Speed of sound, v=330 m/s)⇒f=1650Hz