The distance between a pair of parallel lines $9 x^{2} - 24 x y + 16 y^{2} - 12 x + 16 y - 12 = 0$ .

5

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8

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8 / 5

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5 / 8

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Solution

The correct option is A $5$
distance $= 2 \sqrt{\frac{g^{2} - a c}{a (a + b)}}$
$a = 9, b = 16, g = - 12 / 2 = - 6, c = - 12$

distance $d = 2 \sqrt{\frac{36 - (- 108)}{9 (24)}}$
after solving
$d = 5$

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