Question

The distance between an object and a divergent lens is m times greater than the focal length of the lens. How many times will the image be smaller than the object?

• A. m
• B. $\frac{1}{m}$
• C. (m+1)
• D. (m-1)

Answer 1

The correct option is C (m+1)

Let the focal length of the diverging lens be f (f < 0).
So, according to the question,
Object distance, u = mf (m > 0)
Magnification, $m=\frac{v}{u}=\frac{f}{u+f}$$=\frac{f}{mf+f}=\frac{1}{m+1}$
Hence, the correct answer is option (c).