Question

The distance between an object and a divergent lens is $m$ times the focal length of the lens. The linear magnification produced by the lens is

• A. $m$
• B. $\frac{1}{m}$
• C. $m+1$
• D. $\frac{1}{m+1}$

Answer 1

The correct option is D $\frac{1}{m+1}$

Given, $u=-mf$
$\therefore \frac{1}{v}-\frac{1}{(-mf)}=-\frac{1}{f}$
$\Rightarrow \frac{1}{v}=-\frac{1}{f}(1+\frac{1}{m})$
$\Rightarrow -\frac{v}{f}=\frac{m}{m+1}$
$\Rightarrow -\frac{v}{u}=\left(\frac{1}{1+m}\right)$