The distance between an object and the screen is 100cm. A lens produces an image on the screen when the lens is placed at either of the positions 40cm apart. The power of the lens is nearly
A
3diopter
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B
5diopter
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C
2diopter
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D
9diopter
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Solution
The correct option is A5diopter At first position of lens, let the distance of lens from object and screen be x and y, respectively. ∴x+y=100....(i) ∴ At second position of lens, the distance of lens from object and screen shall be y and x, respectively. ∴y−x=40....(ii) Solving Eqs. (i) and (ii), we get y=70cm=70100m and x=30cm=30100m Therefore, the power of lens is 1f=1y+1x=10070+(10030)=10021≈5diopter.