Question

The distance between an octahedral and tetrahedral void in fcc lattice would be

• A. $\sqrt{3}a$
• B. $\frac{\sqrt{3a}}{2}$
• C. $\frac{\sqrt{3a}}{3}$
• D. $\frac{\sqrt{3}a}{4}$

Answer 1

The correct option is D $\frac{\sqrt{3}a}{4}$

Distance between an octahedral and tetrahedral void in fcc lattice is $\frac{\text{body diagonal}}{4}$ $=\frac{\sqrt{3}a}{4}$