wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The distance between any two I atoms in BI3 is found to be 3.46 oA. What is the covalent radius of boron. If covalent radius of I atom is 1.33 oA? (Assume all bonds are single bonds in BI3)
(Given, 3=1.73, 3.99=1.99)

A
0.66 oA
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1.77 oA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.2 oA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1.32 oA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0.66 oA
The hybridisation of BI3 is sp2
So, it has trigonal planar shape.
B I B=120o
Given,
The distance between two I atoms is3.46 Ao.
Covalent radius of I atom is =1.33 oA

Since,
BI bond length are same, thus B I I=30o

If we draw a perpendicular Bx, then length of Ix would be 1.73 oA
Now,
tan 30o=BxIx
13=Bx1.73
Bx=1.731.73=1
Again,
BI2=Bx2+Ix2
=12+(1.73)2
=3.99
BI=1.99
Let, the covalent radius of B=Z

According to the question,
1.33+Z=1.99
Z=0.66oA

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Size of an Atom or Ion
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon