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Question

On a string, the space between nodes is 5 cm. The transverse wave has a velocity of 2 ms -1. The frequency is then


A

5Hz

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B

10Hz

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C

20Hz

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D

15Hz

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Solution

The correct option is C

20Hz


Step: 1 Given data:

Distance between two nodes = 5cm.

The velocity of a transverse wave v=2ms-1.

Step: 2 Formula used:

The distance between two nodes =λ2.

Frequency f=vλ

Step: 3 Solve for frequency:

Distance between two nodes =λ2.

Therefore, λ2=5

λ=10cmor0.1m

Frequency f=vλ=20.1

=20Hz

Hence, option C is correct.


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