Question

The distance between parallel sides of a trapezium is $15cm$ and the length of the line segment joining the mid-points of its non-parallel sides is $26cm$. Find the area of the trapezium.

• A. $390c{m}^2$
• B. $490c{m}^2$
• C. $130c{m}^2$
• D. $190c{m}^2$

Answer 1

The correct option is A $390c{m}^2$

Given: $EF=26cm$

Now, we know that,

$\Rightarrow EF=\frac{1}{2}\times (AB+CD)$

$\therefore EF=\frac{1}{2}\times (AB+CD)=26cm$

Now,

Area of trapezium $ABCD=\frac{1}{2}\times h\times (AB+CD)$

$=26\times 15$

$=390c{m}^2$