The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is 1.1 $o A$ . Given, mass of carbon atom is 12 a.m.u. and mass of oxygen atom is 16 a.m.u., calculate the position of the centre of mass of the carbon monoxide molecule

6.3

from the carbon atom

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from the oxygen atom

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0.63

from the carbon atom

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0.12

from the oxygen atom

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Solution

The correct option is C 0.63 from the carbon atom
Let carbon atom is at the origin and the oxygen atom is placed at x-axis
$m_{1} = 12, m_{2} = 16,_{1} = 0 ˆ i + 0 ˆ j a n d_{2} = 1.1 ˆ i + 0 ˆ j$
$\to r = \frac{m_{1}_{1} + m_{2}_{2}}{m_{1} + m_{2}} = \frac{16 \times 1.1}{28} ˆ i$
$\to r = 0.63 ˆ i$ i.e. 0.63 $o A$ from carbon atom.

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The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is 1.1 oA. Given, mass of carbon atom is 12 a.m.u. and mass of oxygen atom is 16 a.m.u., calculate the position of the centre of mass of the carbon monoxide molecule

The correct option is C 0.63 from the carbon atomLet carbon atom is at the origin and the oxygen atom is placed at x-axis m1=12,m2=16,→r1=0ˆi+0ˆjand→r2=1.1ˆi+0ˆj →r=m1→r1+m2→r2m1+m2=16×1.128ˆi →r=0.63ˆi i.e. 0.63 oA from carbon atom.

The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is 1.1 $o A$ . Given, mass of carbon atom is 12 a.m.u. and mass of oxygen atom is 16 a.m.u., calculate the position of the centre of mass of the carbon monoxide molecule