The distance between the centres of $C$ and $O$ atom in the $C O$ gas molecule is $1.13 ˚ A$ , locate the centre of mass of the gas molecule relative to $C$ atom.

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Solution

$C_{x} = \frac{12 \times 0 + 16 \times 1.13}{12 + 16} = \frac{18.08}{28} = 0.64 A^{0}$

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The distance between the centres of C and O atom in the CO gas molecule is 1.13˚A, locate the centre of mass of the gas molecule relative to C atom.

Cx=12×0+16×1.1312+16=18.0828=0.64A0

The distance between the centres of $C$ and $O$ atom in the $C O$ gas molecule is $1.13 ˚ A$ , locate the centre of mass of the gas molecule relative to $C$ atom.

$C_{x} = \frac{12 \times 0 + 16 \times 1.13}{12 + 16} = \frac{18.08}{28} = 0.64 A^{0}$