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Question

The distance between the foci of a hyperbola is 16 and its eccentricity is 2 , then find the equation of hyperbola.

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Solution

As e=2 and 2ae=16
Thus,2a=8
a=82×22=822=42
Thus,x2a2y2b2=1
x2(42)2y2(42)2=1
x232y232=1
or x2y2=32

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