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Question

The distance between the foci of the hyperbola 9x216y2+18x+32y151 = 0 is


A

2

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B

8

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C

10

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D

6

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Solution

The correct option is C

10


9x216y2+18x+32y151=0

9(x2+2x)16(y22y) = 151

9(x+1)216(y1)2=916+151 = 1414

(x+1)216(y1)29=1

a = 4 ,b=3

e = 1+916=54

5S1=2ae=2.4.54 = 10


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