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Byju's Answer
Standard XII
Physics
Vector Component
The distance ...
Question
The distance between the focus and directrix of the conic
(
√
3
x
−
y
2
)
=
48
(
x
+
√
3
y
)
is
A
24
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B
48
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C
6
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D
12
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Solution
The correct option is
C
24
⟹
y
2
−
2
(
−
24
√
3
)
y
+
(
−
24
√
3
)
2
=
(
√
3
−
48
)
x
+
(
−
24
√
3
)
2
Constant term does not change length of focus and directrix
⟹
(
y
+
24
√
3
)
2
=
−
4
(
12
−
√
3
4
)
x
Distance
=
2
(
12
−
√
3
4
)
≈
23.14
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0
Similar questions
Q.
The equation of a conic with directrix
3
x
+
4
y
−
5
=
0
and focus (0, 0) is given as
x
2
+
y
2
=
(
3
x
+
4
y
−
5
)
2
. Find eccentricity of the conic.
__
Q.
Find the equation of the ellipse in the following cases:
(i) focus is (0, 1), directrix is x + y = 0 and e =
1
2
(ii) focus is (−1, 1), directrix is x − y + 3 = 0 and e =
1
2
(iii) focus is (−2, 3), directrix is 2x + 3y + 4 = 0 and e =
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5
(iv) focus is (1, 2), directrix is 3x + 4y − 5 = 0 and e =
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2
.