The distance between the genes a, b, c and d in mapping units are:
a - d = 3.5; b - c = 1; a - b = 6; c - d = 1.5; a - c =5.
Find out the sequence of arrangement of these genes.
A
acdb
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B
abcd
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C
acbd
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D
adbc
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E
adcb
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Solution
The correct option is E adcb a ---------------- d -------------------------- c --------------------------- b 3.5 1.5 1 {-------------------------- 5-------------------} I------------------------------------------ 6----------------------------------I