wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The distance between the line r=2^i2^j+3^k+λ(^i^j+4^k) and the plane r.(^i+5^j+^k)=5 is

A
1033
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
103
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
109
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D none
r=2ˆi2ˆj+3ˆk+λ(ˆiˆj+4ˆk)x21=y+21=z34r.(ˆi+5ˆj+ˆk)=5x+5y+z=5sinθ=15+41827=0
Hence, line and plane are parallel.
Distance b/w line and plane.
Again,
x21=y+21=z34
x+5y+z=5
d=|2+5(2)3|27=527
Hence length of perpendicular =527
Which is distance b/w line and plane.
Then,
Option D is correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Angle between Two Planes
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon