Question

The distance between the lines $3x-4y+9=0$ and $6x-8y-15=0$ is ___ units

• A. $\frac{20}{33}$
• B. $\frac{10}{33}$
• C. $\frac{33}{10}$
• D. $\frac{33}{20}$

Answer 1

The correct option is C $\frac{33}{10}$

The lines $3x-4y+9=0$ and $2(3x-4y)-15=0$ are parallel.
Hence distance between them will be
$\frac{|9+15/2|}{\sqrt{3^2+4^2}}=\frac{33}{10}$ units