Question

The distance between the lines $3x+4y=9$ and $6x+8y=15$ is

• A. $\frac{3}{2}$
• B. $\frac{3}{10}$
• C. $6$
• D. None of these

Answer 1

The correct option is B $\frac{3}{10}$

Given lines: $3x+4y=9$ & $6x+8y=15$, $3x+4y=15/2$

Distance between lines= $\frac{9-\frac{15}{2}}{\sqrt{(3{)}^2+(4{)}^2}}$

$=\frac{18-15}{2\times 5}=\frac{3}{10}$ .