The distance between the lines $5 x - 12 y + 2 = 0$ and $5 x - 12 y - 3 = 0$ , is

5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{5}{13}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1}{13}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{5}{13}$
$5 x - 12 y + 2 = 0, 5 x - 12 y - 3 = 0$
Since, these lines are parallel .
So, $d = \frac{| c_{1} - c_{2} |}{\sqrt{a^{2} + b^{2}}}$
$\Rightarrow d = \frac{5}{13}$

Suggest Corrections

Similar questions

5 x - 12 y + 65 = 0

5 x - 12 y - 39 = 0

5 x + 12 y + 11 = 0, 5 x + 12 y + 37 = 0

(x - 5)^{2} + (y + 3)^{2} = 1

5 x + 12 y - 4 = 0

5 x - 12 y - 14 = 0

5 x - 12 y + 12 = 0

Join BYJU'S Learning Program