Question

The distance between the lines $3x+4y=9$ and $6x+8y+15=0$ is

• A. $\frac{3}{10}$
• B. $\frac{33}{10}$
• C. $\frac{33}{5}$
• D. none of these

Answer 1

Answer: (B)

$\frac{33}{10}$

Given:

$6x+8y-18=0$

$6x+8y+15=0$

Using above mentioned formula, we get

$d=\left|\frac{15-(-18)}{\sqrt{(6{)}^2+(8{)}^2}}\right|$

$d=\frac{33}{10}$

Hence, option 'B' is correct.