The distance between the origin and P (3,√5,2) is ___ units.
√7
7√5
7
8
O≡ (0, 0), P ≡ (3,√5,2)
Using distance formula we have,
OP = √(3√5)2+(2)2
=√45+4
=√49
= 7 units
If y=√√7+7+√8+2√7−√7, then the value of y will be: