The correct option is A 1√5
Putting x=0 in the given curve, we obtain y=1.
So, the given point is (0,1).
Now, y=e2x+x2
⇒dydx=2e2x+2x
⇒(dydx)0,1=2
The equation of the tangent at (0,1) is
y−1=2(x−0)
⇒2x−y+1=0 ...(1)
Required distance is the length of perpendicular from (0,0) on the line (1)
Required distance =1√5