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Question

The distance between the origin and the tangent to the curve y=e2x+x2 drawn at the point x=0 is

A
15
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B
25
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C
15
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D
23
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Solution

The correct option is A 15
Putting x=0 in the given curve, we obtain y=1.
So, the given point is (0,1).

Now, y=e2x+x2
dydx=2e2x+2x
(dydx)0,1=2

The equation of the tangent at (0,1) is
y1=2(x0)
2xy+1=0 ...(1)

Required distance is the length of perpendicular from (0,0) on the line (1)
Required distance =15

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