The distance between the pair of parallel lines represented by x2+4xy+4y2+3x+6y−4=0 is ___ units
A
√5
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B
1√5
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C
3
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D
1√3
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Solution
The correct option is A√5 x2+4xy+4y2+3x+6y−4=0 ⇒(x+2y)2+3(x+2y)−4=0 ⇒((x+2y)+4)((x+2y)−1)=0
Therefore, the lines are x+2y+4=0
and x+2y−1=0
Required distance =|4−(−1)|√1+4 =5√5=√5 units