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Question

The distance between the pair of parallel lines represented by x2+4xy+4y2+3x+6y4=0 is ___ units

A
5
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B
15
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C
3
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D
13
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Solution

The correct option is A 5
x2+4xy+4y2+3x+6y4=0
(x+2y)2+3(x+2y)4=0
((x+2y)+4)((x+2y)1)=0
Therefore, the lines are
x+2y+4=0
and x+2y1=0
Required distance =|4(1)|1+4
=55=5 units

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