The distance between the parallel lines 8x+6y+5=0 and 4x+3y-25=0 is

7/3

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9/2

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11/2

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5/4

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Solution

The correct option is C
11/2

Distance between parallel lines ax + by + $c_{1}$ = 0 and ax + by + $c_{2}$ = 0 is $\frac{| c_{1} - c_{2} |}{\sqrt{a^{2} + b^{2}}}$

Given lines are 8x+6y+5 = 0 and 4x + 3y - 25 = 0

$\Rightarrow$ 8x + 6y - 50 = 0

$∴$ Required distance = $\frac{5 + 50}{\sqrt{8^{2} + 6^{2}}} = \frac{55}{10} = \frac{11}{2}$

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Similar questions

The distance between the parallel lines $8 x + 6 y + 5 = 0$ and $4 x + 3 y - 25 = 0$ is

Determine the distance between the following pair of parallel lines:

(i) $4 x - 3 y - 9 = 0$ and $4 x - 3 y - 24 = 0$

(ii) $8 x + 15 y - 34 = 0$ and $8 x + 15 y + 31 = 0$

(iii) $y = m x + c$ and $y = m x + d$

(iv) $4 x + 3 y - 11 = 0$ and $8 x + 6 y = 15$

2 x - 3 y + 6 z + 1 = 0

4 x - 6 y + 12 z - 5 = 0

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