Question

The distance between the parallel lines $8x+6y+5=0$ and $4x+3y-25=0$ is

• A. 7/3
• B. 9/2
• C. 11/2
• D. 5/4

Answer 1

The correct option is C

11/2

Distance between parallel lines $ax+by+c_1=0$ and $ax+by+c_2=0$ is $\frac{|c_1-c_2|}{\sqrt{a^2+b^2}}$

Given lines are $8x+6y+5=0$ and
$4x+3y-25=0$ or $8x+6y-50=0$

$\therefore$ Required distance = $\frac{5+50}{\sqrt{8^2+6^2}}=\frac{55}{10}=\frac{11}{2}$