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Question

The distance between the points (0, 5) and (5, 0) is __________.

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Solution

The distance between x1, y1 and x2, y2 is x2-x12+y2-y12.

Therefore, the distance between the points (0, 5) and (5, 0)=5-02+0-52
=52+-52=25+25=50=52

Hence, the distance between the points (0, 5) and (5, 0) is 52 units.

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