The distance between the points (0, 5) and (5, 0) is

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5 \sqrt{2}

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2 \sqrt{5}

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Solution

The correct option is C $5 \sqrt{2}$
$T h e d i s t a n c e d b e t w e e n t w o p o i n t s (x_{1}, y_{1}) & (x_{2}, y_{2}) i s d = \sqrt{{(x_{1} - x_{2})}^{2} + {(y_{1} - y_{2})}^{2}} T h e g i v e n p o i n t s a r e (x_{1}, y_{1}) = (0, 5) a n d (x_{2}, y_{2}) = (5, 0) ∴ d = \sqrt{{(0 - 5)}^{2} + {(5 - 0)}^{2}} = 5 \sqrt{2} u n i t s . A n s - O p t i o n B$

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Similar questions

Q. Question 4
The distance between the points (0, 5 ) and ( - 5, 0) is:
(A) 5
(B)

5 \sqrt{2}

(C)

2 \sqrt{5}

(D) 10

Q. The distance between the points

(0, 5), (- 5, 0)

Q. The distance between the given points

K (0, - 5)

and

L (- 5, 0)

Find the distance between planes 2x + 5y + 4z - 3 = 0 and 2x + 5y + 4z- 5 = 0.

Find the equation of the lines through the point of intersection of the lines x-3y+1 = 0 and 2x+5y-9 = 0 and whose distance from the origin is $\sqrt{5}$ .

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The distance between the points (0, 5) and (5, 0) is

The correct option is C 5√2Thedistancedbetweentwopoints(x1,y1)&(x2,y2)isd=√(x1−x2)2+(y1−y2)2Thegivenpointsare(x1,y1)=(0,5)and(x2,y2)=(5,0)∴d=√(0−5)2+(5−0)2=5√2units.Ans−OptionB