The distance between the points (–4, 7) and (1, –5) is ___ units.
√13
13
√14
14
Distance between points (x1,y1) and (x2,y2) = √(x2−x1)2+(y2−y1)2
⇒ Distance between the points (–4, 7) and (1, –5) =√(1−(−4))2+(−5−7)2 =√52+(12)2 =√169 =13 units
The distance (in units) between the points (1, 3), (5, 6) is _____.