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Question

The distance between the points (–4, 7) and (1, –5) is ___ units.


A

13

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B

13

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C

14

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D

14

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Solution

The correct option is B

13


Distance between points (x1,y1) and (x2,y2) = (x2x1)2+(y2y1)2

Distance between the points (–4, 7) and (1, –5)

=(1(4))2+(57)2

=52+(12)2

=169

=13 units


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