The distance between the points (5, 5) and (3, 3) is
2√2 units
The distance between two points (x1,y1) and (x2,y2) is given by √(x2−x1)2+(y2−y1)2.
Distance between points (5,5) and (3,3)
=√(3−5)2+(3−5)2=√4+4=2√2 units
Hence, the distance between the given points is 2√2 units.