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Question

The distance between the points (cos q, sin q) and (sin q, – cos q) is ___.


A

3

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B

2

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C

2

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D

1

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Solution

The correct option is B

2


The distance between the points (x1,y1) and (x2,y2) is (x2x1)2+(y2y1)2

Applying distance formula, we get:

Distance=((sinqcosq)2+(cosqsinq)2

=sin2q2sinqcosq+cos2q+cos2q+2sinqcosq+sin2q


=2(cos2q+sin2q)=2 (cos2q+sin2q=1)


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