The distance between the points $(0, 0)$ and $(- 4, 3)$ is

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Solution

Let $A (x_{1}, y_{1}) = (0, 0)$ and $B (x_{2}, y_{2}) = (- 4, 3)$

$∴$ Distance $A B = \sqrt{{(x_{2} - x_{1})}^{2} + {(y_{2} - y_{1})}^{2}}$

$∴ A B = \sqrt{{(- 4 - 0)}^{2} + {(3 - 0)}^{2}}$

$= \sqrt{16 + 9} = \sqrt{25} = 5$ units

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The distance between the points (0,0) and (−4,3) is

Let A(x1,y1)=(0,0) and B(x2,y2)=(−4,3)∴ Distance AB=√(x2−x1)2+(y2−y1)2∴AB=√(−4−0)2+(3−0)2=√16+9=√25=5 units

The distance between the points $(0, 0)$ and $(- 4, 3)$ is

Let $A (x_{1}, y_{1}) = (0, 0)$ and $B (x_{2}, y_{2}) = (- 4, 3)$

$∴$ Distance $A B = \sqrt{{(x_{2} - x_{1})}^{2} + {(y_{2} - y_{1})}^{2}}$

$∴ A B = \sqrt{{(- 4 - 0)}^{2} + {(3 - 0)}^{2}}$

$= \sqrt{16 + 9} = \sqrt{25} = 5$ units