The distance between the points P(3, 2) and Q(–4, 5) is
4
8
√73
√58
Given P(3,2), Q(-4,5) ∵ Distance between points (x1, y1), (x2, y2)is√(x2−x1)2 + (y2−y1)2 ∴PQ=√(−4−3)2+(5−2)2=√49+9=√58
The distance between the points (-1, 5) and (2, 1) is ___ units.